Question

Como resolver as seguintes proporções .

a) 1- x/18 = 40/24

b) x-3/18 = 21/42

Answer 1

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$\large\texttt{Calcular x nas seguintes propor\c{c}\~oes:}$


$\large\begin{array}{l} \mathtt{a)~~\dfrac{1-x}{18}=\dfrac{40}{24}}\end{array}$

$\large\begin{array}{l}\texttt{Em qualquer propor\c{c}\~ao, o produto dos extremos \'e}\\\texttt{igual ao produto dos meios:}\\\\ \mathtt{(1-x)\cdot 24=18\cdot 40}\\\\ \mathtt{24-24x=720}\\\\ \mathtt{-24x=720-24}\\\\ \mathtt{-24x=696} \end{array}$

$\large\begin{array}{l} \mathtt{x=\dfrac{696}{-24}}\\\\ \boxed{\begin{array}{c}\mathtt{x=-\,29}\end{array}}\qquad\checkmark \end{array}$

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$\large\begin{array}{l} \mathtt{b)~~\dfrac{x-3}{18}=\dfrac{21}{42}}\\\\ \mathtt{(x-3)\cdot 42=18\cdot 21}\\\\ \mathtt{42x-126=378}\\\\ \mathtt{42x=378-126}\\\\ \mathtt{42x=252}\end{array}$

$\large\begin{array}{l} \mathtt{x=\dfrac{252}{42}}\\\\ \boxed{\begin{array}{c}\mathtt{x=6}\end{array}}\qquad\checkmark\end{array}$


$\large\texttt{Bons estudos! :-)}$


Tags:  razão proporção propriedade produto meios extremos equação solução resolver