Question

??????????????????????

Answer 1

Explicação passo a passo:

2)

Sendo a equação na forma

$\boxed{x^2-Sx+P=0}$

a)

S =x' + x" = 5 + 2 = 7

P = x' . x" = 5 × 2 = 10

$\boxed{x^2-7x+10=0}$

b)

S= x' + x" = 1 + 1 = 2

P = x' × x" = 1×1 = 1

$\boxed{x^2-2x+1=0}$

c)

S = x' + x" = 2 + 0 = 2

P = x' × x" = 2 × 0 = 0

$\boxed{x^2-2x=0}$

d)

S = x' + x" = 0 - 3 = -3

P = x' . x" = 0× ( -3) = 0

x² - (-3)x =0

$\boxed{x^2+3x=0}$

e)

S = x' + x" = 5 -5 = 0

P= x' .x" = 5 × ( - 5 ) = -25

$\boxed{x^2-25=0}$

f)

S = x' + x" = 0 + 0 = 0

P = x' .x" = 0 × 0 = 0

$\boxed{x^2=0}$

g)

S = x' + x" = 3 + 5 = 8

P = x' .x" = 3 × 5 = 15

$\boxed{x^2-8x+15=0}$