Question

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Answer 1

$\mathrm{Sejam\ os\ pesos\ da\ pessoa\ na\ Terra\ e\ em\ Netuno\ representados,}\\ \mathrm{respectivamente,\ por}\ W_T\ \mathrm{e}\ W_N.$

$\mathrm{Sabemos\ que}\ \dfrac{W_{\mathrm{T}}}{W_{\mathrm{N}}}=\dfrac{5}{7}\Longrightarrow \boxed{W_{\mathrm{N}}=\dfrac{7}{5}W_{\mathrm{T}}}$

$\mathrm{Se}\ m=60\ \text{kg}\ \mathrm{e}\ g\approx9.81\ \mathrm{m/s^2}\Longrightarrow W_{\mathrm{T}}=mg\ \therefore\ \boxed{W_{\mathrm{T}}\approx588.6\ \text{N}}$

$\mathrm{Logo}\ W_{\mathrm{N}}\approx\dfrac{7}{5}(588.6)\ \therefore\ \boxed{W_{\mathrm{N}}\approx824.04\ \text{N}}$