Question

x2-x-12=0

me ajuda pfv

Answer 1

$x^2-x-12=0$

Coeficientes: a = 1, b = -1 e c = -12

$\Delta=b^2-4ac\\\Delta=(-1)^2-4\times1\times(-12)\\\Delta=1+48\\\Delta=49$


$x=\frac{-b+-\sqrt{\Delta}}{2a}\\\\x=\frac{-(-1)+-\sqrt{49}}{2\times1}\\\\x=\frac{1+-7}{2}\\\\x'=\frac{1+7}{2}=\frac{8}{2}=4\\\\x"=\frac{1-7}{2}=\frac{-6}{2}=-3$


Espero ter ajudado.
Bons estudos! :)