Question

x2 + 8x + 12 =0 resolva as equaçoes

Answer 1

x²+8x+12=0

$Δ = b ^{2} - 4ac$

$Δ = 8^{2} - 4 \times 1 \times 12$

$Δ = 64 - 48$

$Δ = 16$

$x = (- b± \sqrt{Δ} ) \div 2 \times a$

$x = ( - 8±4) \div 2$

$x1 = ( - 8 + 4) \div 2 = - 4 \div 2 = - 2$

$x2 = (- 8 - 4) \div 2 = - 12 \div 2 = - 6$

S={-2, -6}