Question

X(x-2)=2(x+6) me ajudar por favor

Answer 1

Resposta:

x²-2x=2x+12

x²-2x-2x-12=0

x²-4x-12=0

Bháskara ==> ∆=b²-4ac

∆=(-4)²-4.1.(-12)

∆=16+48

∆=64

x=b+-√∆/2a

x=(-4)+-√64/2.1

x=-4+-8/2

Encontre as raízes

x1=-4+8/2=4/2=2

x2=-4-8/2=-6