Question

(x − 3)^2 − (4 − x)^2 > x /2

Answer 1

$(x - 3)^2 - (4 - x)^2 > \frac{x}{2}$

$(x^2 - 6x+9) - (16-8x + x^2) > \frac{x}{2}$

$x^2-6x+9-16+8x-x^2>\frac{x}{2}$

$2x-7>\frac{x}{2}$

$2(2x-7)>x$

$4x-14>x$

$4x-x>14$

$3x>14$

$x>\frac{14}{3}$