Question

Uma função é dada por f(x) = 162.(2/3)^x determine: a) f(1) b) f(2) c) f(-1)

Answer 1

f(x) = 162.(2/3)^x

a) F(1)= 162.(2/3)^1
F(1)= 162.(2/3)
F(1)= 108

b) F(2) = 163. (2/3)^2
F(2)= 162. (4/9)
F(2)= 72

c) F(-1)= 162.(2/3)^-1
F(-1)= 162. (3/2)
F(-1) = 243