Question

Two small pitchers and one large pitcher can hold 8 cups of water. One large pitcher minus one small pitcher constitutes 2 cups of water. How many cups of water can each pitcher hold?

Answer 1

x- small pitcher

y=large pitcher

$\left \{ {{2x+y=8} \atop {y-x=2}} \right.$

If done algebraically:

$\left \{ {{2x+y=8} \atop {-x+y=2}} \right.$

Subtract:

$3x=6 \\ \\ x= \frac{6}{3} \\ \\ x=2$

The small pitcher holds 2 cups of water

$2.2+y=8 \\ \\ 4+y=8 \\ \\ y=8-4 \\ \\ y=4$

Thr large pitcher holds 4 cups of water