Question

três n consecutivos tem soma igual a 339. qual o maior deles? 112 113 114 115 116

Answer 1

a+b+c = 339
112+113+114 = 339

Maior algarismo: 114

Answer 2

$\large\boxed{\begin{array}{l} n + n + 1 + n + 2 = 339 \\ \\ 3n + 3 = 339 \\ \\ 3n = 339 - 3 \\ \\ 3n = 336 \\ \\ n = \dfrac{336}{3} \\ \\ \boxed{n=112 \: \: (1)} \\ \\ n = 112 + 1 \\ \\ \boxed{n = 113 \: \: (2)} \\ \\ n = 113 + 1 \\ \\ \boxed{n = 114 \: \: (3)} \\ \\ \rm{depois \: dos\, c\acute{a}lculos\, conclu\acute{i}mos\, }\\ \rm{ que \,o \, maior\, dos \, n\acute{u}meros\,\acute{e}:} \\ \\ \red{\Large\boxed{\begin{array}{l} \Large\boxed{\begin{array}{l} \huge\therefore \: 114 \: \end{array}}\end{array}}} \end{array}}$