Question

$x { }^{2} + 2x - 3 = 0$
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Answer 1

Por Bháskara temos

Δ=b²-4ac -> Δ=2²-4.1.-3 -> Δ=4+12 -> Δ=16

$x1 = \frac{-b+\sqrt{16}}{2a}$ -> $x1 = \frac{-2+4}{2}$ -> x1 = 1

$x2 = \frac{-b-\sqrt{16}}{2a}$ ->  $x2 = \frac{-2-4}{2}$  -> x2=-3