Question

$f(x) = {x}^{2} + 2$
$g(x) = 2x - 1$
então F[g(x)] é:

a)x□

b)-2x□

c)4x□-4x+3

d)x□-4x+3

Answer 1

f(x) = x^2 + 2 g(x) = 2x - 1  = F[g(x)] = (2x - 1)^2 + 2 = (2x)^2 - 2.1.2x + 1 + 2 = 4x^2 - 4x + 3 (c)