Question

simplifique usando fatoração de fator comum: 9a²c + 18ab²/ 72 a³bc + 108 a²b³?????

Answer 1

$\dfrac{9a^2c + 18ab^2}{ 72 a^3bc + 108 a^2b^3} \\ \\ \\ \dfrac{9a(ac + 2b^2)}{ 36a^2b(2ac + 3b^2)} \\ \\ \\ => \dfrac{ac + 2b^2}{4ac(2ac + 3b^2)}$