Question

simplifique :
A) 6!/4!=
B)3!/5!=
C)7!/4!3!=
D)3!/5=
F)(n-2)!/(n+1)!=​

Answer 1

Resposta:

Boa tarde!

Explicação passo-a-passo:

Vamos lá!

$a)\dfrac{6!}{4!} =\dfrac{6.5.4!}{4!} =6.5=30\\\\\\b)\dfrac{3!}{5!} =\dfrac{3!}{5.4.3!} =\dfrac{1}{20} \\\\\\c)\dfrac{7!}{4!3!} =\dfrac{7!}{(4.3.2)(3.2)} =\dfrac{7.6.5.4.3.2!}{24.6} =\dfrac{5040}{144} =35\\\\\\\dfrac{3!}{5} =\dfrac{3.2}{5} =\dfrac{6}{5} \\\\\\\dfrac{(n-2)!}{(n+1)!} =\dfrac{(n-2)(n+1)n!}{(n+1)n!} =n-2$