Question

sendo x=(-1/2):(+2),calcule
A)O QUADRADO DO NÚMERO X
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B)O CUBO DO NÚMERO X​

Answer 1

Determinar valor de x:

$\sf x = - \dfrac{1}{2} \div (+2)$

$\sf x =- \dfrac{1}{2} * \dfrac{1}{2}$

$\sf x = - \dfrac{1*1}{2*2}$

$\sf x = - \dfrac{1}{4}$

Descoberto o valor de x, calcular:

A) o quadrado de x

$\sf x = \bigg(- \dfrac{1}{4}\bigg)^2$

$\sf x = \bigg(- \dfrac{1}{4}\bigg)*\bigg(- \dfrac{1}{4}\bigg)$

$\red{\sf x = + \dfrac{1}{16}}$

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B) o cubo de x

$\sf x = \bigg(- \dfrac{1}{4}\bigg)^3$

$\sf x = \bigg(- \dfrac{1}{4}\bigg)*\bigg(- \dfrac{1}{4}\bigg)*\bigg(- \dfrac{1}{4}\bigg)$

$\red{\sf x = - \dfrac{1}{64}}$

Answer 2

Ok , vamos lá !

Resolução de X

$\sf x = - \dfrac{1}{2} :2$

$\sf x = - \dfrac{1}{2} : \dfrac{2}{1}$

$\sf x = - \dfrac{1}{2} \cdot \dfrac{1}{2}$

$\blue{\sf x = - \dfrac{ 1}{4} }$

Letra A

$\sf x = \bigg(- \dfrac{ 1}{4} \bigg)^{2}$

$\sf x = \bigg(- \dfrac{ 1}{4} \bigg)\cdot \bigg(- \dfrac{ 1}{4} \bigg)$

$\blue{\sf x = \dfrac{ 1}{16} }$

Letra B

$\sf x = \bigg(- \dfrac{ 1}{4} \bigg)^{3}$

$\sf x = \dfrac{ 1}{16} \cdot \bigg(- \dfrac{ 1}{4} \bigg)$

$\blue{\sf x = - \dfrac{ 1}{64} }$

Bons estudos .