Sendo A=a²-4ab+4b²,B=a²-4b² e C=a²-2ab,calcule o que se pede
a)m.d.c. (A,B,C)=
b)m.m.c.(A,C)=
c)m.d.c.(A,B)-m.d.c.(B,C)=
d)m.m.c.(A,C)
___________=
m.d.c.(A,B,C)
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A=a²-4ab+4b² ==> (a - 2b)²
B=a²-4b² ==> (a + 2b)( a - 2b)
C= a²-2ab ==> a(a - 2b )
a)m.d.c. (A,B,C)= ( a - b )
b)m.m.c.(A,C)= a(a - 2b)²
c)m.d.c.(A,B)-m.d.c.(B,C)= a - 2b - ( a - 2b) ==. a - 2b - a + 2b ==> 0
d)m.m.c.(A,C) = a(a - 2b)² => a( a - b )
m.d.c.(A,B,C) ( a - b )
B=a²-4b² ==> (a + 2b)( a - 2b)
C= a²-2ab ==> a(a - 2b )
a)m.d.c. (A,B,C)= ( a - b )
b)m.m.c.(A,C)= a(a - 2b)²
c)m.d.c.(A,B)-m.d.c.(B,C)= a - 2b - ( a - 2b) ==. a - 2b - a + 2b ==> 0
d)m.m.c.(A,C) = a(a - 2b)² => a( a - b )
m.d.c.(A,B,C) ( a - b )
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