Question

Sendo(4*)²=16.2*²,qual éo valor de x*?

Answer 1

(4^x)² = 16. 2^x²

(4)^2x = 2⁴. 2^x²

(2²)^2x = 2⁴. 2^x²

(2)^4x = (2)^4+x²

x²+4 =4x

x² -4x +4 = 0

(x -2)² = 0

x -2 = 0

x = 2 ✓