Question

se a=0,666...b=1,333... e c=0,141414... entao a.b elevado a -1 + c é igual á:

Answer 1

a) = $\frac{6}{9}$

b) = $\frac{12}{9}$

c) = $\frac{14}{99}$

a*b^a-1 $a * b^{a-1} + c$$\frac{6}{9} * \frac{12}{9} ^ \frac{6}{9}-1  + \frac{14}{99}$

$\frac{6}{9} * \frac{12}{9} ^ -\frac{1}{3} + \frac{14}{99}$

$\frac{99 \sqrt[3]{ \frac{4}{3}^2 } +28}{198}$