Question

Sabendo que log2 = 0,301 e log3 = 0,477 e log5= 0,699
Calcule:

A) log 15
B) log √3
C) log 7,2

Answer 1

$a)\\log15\\\\log(3\;.\;5)\\\\log3+log5\\\\0,301+0,699\\\\1$

$b)\\log\,\sqrt{3}\\\\log\,3^{\frac{1}{2}}\\\\\frac{1}{2}log3\\\\\frac{1}{2}.0,477\\\\0,2385$

$c)\\log\,7,2\\\\log\left(\frac{72}{10}\right)\\\\log\left(\frac{3^2\,.\,2^3}{10}\right)\\\\(log3^2\,+\,log2^3)-log10\\\\(2log3+3log2)-log10\\\\(2\;.\;0,477+3\;.\;0,301)-1\\\\0,954+0,903-1\\\\0,857$