Question

sabendo log 2=2,66 e log 3=3,48
calcule os logaritmo
a ) log 40

Answer 1

Na realidade, com 4 casas decimais, log2 = 0, 3010 e log3 = 0,4771
Mas se log2 = 2,66 e log3 = 3,48, o log40, daria:
log40 = log 2³ . 5 = log 2³ + log5 = 3 log2 + log(10/2) = 3 log2 + (log10 - log2) =
= 2 log2 + log10 = 2 . 2,66 + 1 = 6,32

Answer 2

$Log~40=log~(4.10)=log~4+log~10=log~ 2^{2} +1= \\ 2log~2+1=2.0,301+1=0,602+1=1,602$