Question

sabe-se que log2=0,3010,log3=0,4771,entao log108será??

Answer 1

Boa tarde Mimi

log(2) = 0.3010
log(3) = 0.4771

108:2
  54:2
  27:3
    9:3
    3:3

log(108) = log(2^2*3^3) 

log(108) =  2log(2) + 3log(3)
log(108) = 0.6020 + 1.4313 

log(108) = 2.0333 

Answer 2

Sabendo que log2 =0,3010 e log3=0,4771

Temos que log108

Log6.18
Log6+log18
Log3.2+log6.3
Log3+log2+log6+log3
Log3+log2+log3+log2+log3

Substituindo os valores

0,4771.3+0,3010.2=1,4313+0,602=2,0333


Resposta: Log108=2,0333