Question

Responda esse cálculo usado Bhaskara:
$2 {x}^{2} + 2x - 60 = 0$
$6 {x}^{2} + 5 + 1 = 0$

$2 {x}^{2 } + x + 5 = 0$
$7 {x}^{2} + x + 1 = 0$
${x}^{2} + 4x + 3 = 0$
$2 {x}^{2} - 5x - 3 = 0$
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Answer 1

$2x^2+2x-60=0$

= $x=5,\:x=-6$

$6x^2+5+1=0$

= $x=i,\:x=-i$

$2x^2+x+5=0\quad \\=\quad x=-\frac{1}{4}+i\frac{\sqrt{39}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{39}}{4}$

$7x^2+x+1=0\quad \\=\quad x=-\frac{1}{14}+i\frac{3\sqrt{3}}{14},\:x=-\frac{1}{14}-i\frac{3\sqrt{3}}{14}$

$x^2+4x+3=0\quad \\\=\quad x=-1,\:x=-3$

$2x^2-5x-3=0\quad \\=\quad x=3,\:x=-\frac{1}{2}$