Question

Resolver a equação exponencial 9 elevado a 2x-1 = 27 elevado 5x+1 preciso parar passar me respondamm

Answer 1

${9}^{2x - 1} = {27}^{5x + 1} \\ ( {3}^{2} {)}^{2x - 1} = ( {3}^{3} {)}^{5x + 1} \\ {3}^{2(2x - 1)} = {3}^{3(5x + 1)} \\ 2(2x - 1) = 3(5x + 1) \\ 4x - 2 = 15x + 3 \\ 4x - 15x = 2 + 3 \\ - 11x = 5 \\ 11x = - 5 \\ \boxed{x = - \frac{5}{11} }$