Question

resolva o seguinte sistema :

3a-2b=7
a+3b=16

Answer 1

$\left \{ {3a-2b=7} \atop {a+3b=16}} \right. \\ \\ \\ _ \frac{1 } {-3} . \left \{ {3a-2b=7} \atop {a+3b=16}} \right. \\ \\ \\ \left \{ {3a-2b=7} \atop {-3a-9b=-48}} \right. \\ \\ -11b=-41 \\ \\ b= \frac{41}{11} \\ \\ \\ a+3( \frac{41}{11})=16 \\ \\ a=16 - \frac{123}{11} \\ \\ a= \frac{53}{11}$