Question

resolva, em R, as seguintes equações:b)log(4x–1)–log(x+2)= logx c)logx+logx2+logx3 = -6

Answer 1

b) $log( \frac{4x-1}{x+2} )=logx$
4x - 1 = x.(x + 2)
4x - 1 = x² + 2x
x² - 2x + 1 = 0
(x - 1)² = 0
x = 1

c) $logx. x^{2} . x^{3}= - 6$
$x^{6} =10^{-6}$
$x^{6} = (10^{-1})^{6}$
$x= 10^{-1} = \frac{1}{10}$