Question

resolva em C a equaçao;
x²-5x+6=0

Answer 1

$x^{2} -5x+6=0 \Delta= b^{2} -4.a.c} = \Delta= -5^{2} -4.1.6= \Delta=25-24=1 x^{1} -+(-5) \sqrt{1} /2=5-1/2=4/2=2 x^{2} -+(-5) \sqrt{1} /2=5+1=6/2=3$


S{2,3}

Answer 2

$\circ \ x^2 - 5x + 6 \\\\ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\\\ x = \frac{5 \pm \sqrt{25 - 4 \cdot 1 \cdot 6}}{2} \\\\ x = \frac{5 \pm 1}{2} \\\\ x_1 = 3 \\ x_2 = 2 \\\\ \text{S} = \{2,3\}$