Matemática, perguntado por Anderson1999, 1 ano atrás

Resolva as expressão abaixo A) (2,65-4):9= B) 5.(3x4,1-7/2)= C)1/3.2/3:1/7= D)16.(-1/4-20.(-0.6)+25= AJUDEM PFV

Soluções para a tarefa

Respondido por ScreenBlack
1
A)\ \dfrac{2,65-4}{9}\\\\ =\dfrac{-1,35}{9}\\\\ =\dfrac{-135}{900}\\\\ =\dfrac{-45}{300}\\\\ 
 =\dfrac{-15}{100}\\\\ \boxed{=\dfrac{-3}{20}}

B)\ 5\times(3\times\frac{(4,1-7)}{2})\\\\ =5\times(3\times\frac{-2,9}{2})\\\\ =5\times\frac{3\times(-2,9)}{2}\\\\ =5\times\frac{-8,7}{2}\\\\ =\frac{5\times-8,7}{2}\\\\ \boxed{=\frac{-43,5}{2}}

C)\ \left(\dfrac{\frac{1}{3}\times\frac{2}{3}}{\frac{1}{7}}\right)\\\\
=\left(\dfrac{\frac{1\times2}{3\times3}}{\frac{1}{7}}\right)\\\\
=\left(\dfrac{\frac{2}{9}}{\frac{1}{7}}\right)\\\\
=\frac{2}{9}\times\frac{7}{1}\\\\
=\frac{2\times7}{9\times1}\\\\
\boxed{=\frac{14}{9}}

D)\ 16\times(\frac{-1}{4}-20\times(-0.6)+25)\\\\
=16\times(\frac{-1}{4}-(-12)+25)\\\\
=16\times(\frac{-1}{4}+12+25)\\\\
=16\times(\frac{-1}{4}+37)\\\\
=16\times(\frac{-1+(4\times37)}{4})\\\\
=16\times(\frac{-1+148}{4})\\\\
=16\times\frac{147}{4}\\\\
=\frac{16\times147}{4}\\\\
=\frac{2.352}{4}\\\\
\boxed{=588}

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Anderson1999: Oks
Respondido por leaborelas
0
a)(2,65-4)/9=(-1,35)_:9= -0,15
B)5.(3X4.1-7/2)= 5.(12,3-3,5) = 5.8,8=44,0

c)1/3.2/3:1/7= 1/3x14/3= 14/9
d)16.(-1/4-20.(-0,6)+25= 16.(-0,25+12)+25= 16.11,75+25=188+25=213.
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