Question

Resolva as equações x^2=4/5x+1/5

Answer 1

x^2-4/5x-1/5=0
a=1,b=-4/5 e c=-1/5
Δ=b²-4ac
Δ=(-4/5)²-4(1)(-1/5)
Δ=16/25 +4/5
Δ=36/25

x=(-b+-√Δ)/2a
x¹=(-(-4/5)+√36/25)/2
x₁=(4/5+6/5)/2
x¹=(10/5)/2
x¹=2/2=1

x²=(4/5-6/5)/2
x²=(-2/5)/2 = -1/5
      
R:(1,-1/5)