Question

Resolva as equações: a) 4^x-1 . 4^x =64 b) 128^-3x= 16^x+2

Answer 1

a) 4ˣ⁻¹ * 4ˣ = 64

4ˣ⁻¹⁺ˣ = 4³

x - 1 + x = 3

x + x = 3 + 1

2x = 4

x = 4/2

x = 2

b) 128⁻³ˣ = 16ˣ⁺²

(2⁷)⁻³ˣ = (2⁴)ˣ⁺²

- 21x = 4x + 8

4x + 21x = -8

25x = -8

x = -8/25