Question

Resolva:
a)(X-2)+5.(2-X)+6.(X+1)=0
b)X+1=12-(3X-2)​

Answer 1

a) $(x-2)+5.(2-x)+6.(x-1)=0\\x-2+5.2-5x+6x-6.1=0\\x-5x+6x-2+10-6=0\\x-5x+6x=2-10+6\\2x=-2\\x=\frac{-2}{2} \\x=-1$

b) $x+1=12-(3x-2)\\x+1=12-3x+2\\x+3x=12+2-1\\4x=13\\x=\frac{13}{4}$