Question

resolva a equação 2^x+2^x+1+2^x+2=28

Answer 1

$2^x+2^x^+^1+2^x^+^2 = 28\\\\ 2^x+2^x*2^1+2^x*2^2 = 28\\\\ 2^x=y\\\\ y+2y+4y=28\\\\\ 7y = 28\\\\ y=\frac{28}{7}\\\\ \boxed{y=4}$

$2^x =y\\\\ 2^x = 4\\\\ 2^x = 2^2\\\\ \boxed{x=2}\\\\\ \boxed{S(2)}$

Answer 2

 2^x+2^x+1+2^x+2=28
 
 2^x+2^x.2^1+2^x.2^2 = 28
2^x+2.2^x+4.2^x = 28
          2^x = 28/7
          2^x = 4
          2^x = 2^2
    
             x = 2