Question

resolva: -5x²+13x-6=0

Answer 1

-5x²+13-6=0
∆=b²-4.a.c
∆=13²-4.(-5).(-6)
∆=169-120
∆=49
x= -b ± √∆ / 2.a
x= -13 ± √49 / 2×5
x= -13 ± 7 / 10
x1= -13+7/10= -0,6
x2= -13-7/10= -2
xv= -b/2.a => -13/2×5 => -1,3
yv= -∆/4.a => -49/4×5 => -49/20= -2,45
Me desculpe se errei alguma coisa