Question

quantos mols correspondem 222g de Ca(OH)2? (MA: Ca= 40u, O= 16u, H= 1u)​

Answer 1

$MM_{Ca(OH)_2} = 40+2*16+2*1 = 74 \\ n = \frac{massa}{MM} = \frac{222}{74} = 3 mol \:$