Question

qual o valor de x nas progressões aritméticas literais ( x + 3; 4x + 2; x-1)

Answer 1

PA (x + 3; 4x + 2; x - 1)

(4x + 2) - (x + 3) = r
(x - 1) - (4x + 2) = r

r = r

(4x + 2) - (x + 3) = (x - 1) - (4x + 2)
4x + 2 - x - 3 = x -1 - 4x - 2
4x - x - x + 4x = -1 - 2 + 3 - 2
6x = -2
x = -2/6 
x = -1/3

PA(-1/3 + 3 ; 4.-1/3 + 2 ; -1/3 - 1)
PA( (-1 +9)/3 ; (-4/3 + 2) ; ((-1 - 3)/3)
PA(8/3 ; ((-4 + 6)/3) ; -4/3)
PA(8/3 ; 2/3 ; -4/3)

Espero ter ajudado.