Question

Qual é o 2 termo dessa PG

Answer 1

Resposta:

Explicação passo-a-passo:

$a_4=a_1.q^{n-1}\\\\\\substituindo\\\\\dfrac{1}{250}=4.q^{4-1}\\\\\dfrac{1}{1000}=q^{3}\\\\q=\sqrt[3]{\dfrac{1}{1000}}\\\\\\q=\dfrac{1}{10}\\\\\\a_2=a_1.q=4.\dfrac{1}{10}=\dfrac{4}{10}=\dfrac{2}{5}$