Question

Preciso resolver um desafio de logaritmos. Logx 2 + 2logx 4+ 3logx 8= -9

Answer 1

Log₂x + 2.Log₄x + 3.Log₈x = -9
Log₂x + 2/2.Log₂x + 3/3.Log₂x = -9
Log₂x + Log₂x + Log₂x = -9
Log₂(x.x.x) = -9
Log₂x³ = -9
x³ = 2⁻⁹
x³ = 1/2⁹
x = ∛1/∛2⁹

x = 1/2³
x = 1/8