Question

Preciso de ajuda com a 105 e 106, preciso dos cálculos tb

Answer 1

105
a
1/4 - 3/4 - 3/2 - 1/2 =
mmc = 4
( 1 - 3 - 6 - 2)//4 = -10/4 = = 5/2 ***
b
3/4 : 2/3 : 9/12 = 3/4 . 3/2 . 12/9 = 108/144 =3/4 ***
c
1/2 + ( - 0,3) + 1/6 =
1/2 + ( - 3/10) + 1/6
1/2 - 3/10 + 1/6 =
mmc = 30
( 15 - 9 + 5)/30 =11/30 ****
d
0,2 + 3/4 - 5/2 - 0,5 =
2/10 + 3/4 - 5/2 - 5/10 =
mmc = 20
( 4 +15 - 50 - 10)/20 = -41/20 **

106
( -2/3)² + ( - 2/3) + ( -2/3)⁰ =
( 4/9)   + ( - 2/3) + (-1 )
4/9 - 2/3 - 1/1 =
mmc = 9
( 4 - 6 - 9)/9 =  - 11/9 ****
b
(2/1 - 1/4 ) - ( 3/1 - 1/2) =
2/1 - 1/4 - 3/1 + 1/2 =
mmc = 4
( 8 - 1 - 12 + 2 )/4 = - 3/4 ***
c
(3/4 - 5/6) :  ( 1/2 + 1/4)
mmc 12
( 9 - 10)/12 : ( 6 + 3)/12
-1/12  : 9/12 = -1/12 * 12/9 = - 12/108  = - 1/9 ***
d
( -1/1 + 1/2) . ( -2/1 - 3/4)
mmc = 12
[ ( -12 + 6 )/12 ] . [ ( -24 - 9)/12] =
( -6/12) . ( -33/12) = 198/144  = 11/8 ***