Question

obtenha, em cada caso, as coordenadas do ponto médio do segmento AB:
A) A(1,7) e B(11,3)
B)A(-6,9)e B(-2,-5)​

Answer 1

$\large\boxed{\begin{array}{l}\tt a)~\sf x_M=\dfrac{x_A+x_B}{2}=\dfrac{1+11}{2}=\dfrac{12}{2}=6\\\\\sf y_M=\dfrac{y_A+y_B}{2}=\dfrac{7+3}{2}=\dfrac{10}{2}=5\\\sf M(6,5)\\\tt b)~\sf x_M=\dfrac{x_A+x_B}{2}=\dfrac{-6-2}{2}=-\dfrac{8}{2}=-4\\\\\sf y_M=\dfrac{y_A+y_B}{2}=\dfrac{9-5}{2}=\dfrac{4}{2}=2\\\sf M(-4,2)\end{array}}$