Question

no triangulo retangulo, determine as medidas de x e y.( use sen 50°=0,76; cos50°= 0,64; Tg60°=1,1 Angulo 50° c.a=y c.o= x h= 3​

Answer 1

Resposta:

$sen50^{\circ}={c.o\over h}\\ \\ 0,76={x\over3}\\ \\ x=3.(0,76)\\ \\\fbox{ x=2,28 }\\ \\ cos50^{\circ}={c.a\over h}\\ \\ 0,64={y\over3}\\ \\ y=3.(0,64)\\ \\\fbox{ y=1,92 }$