Matemática, perguntado por samuel65181, 5 meses atrás

Nas figuras abaixo determine os valores de x e y

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Soluções para a tarefa

Respondido por CyberKirito
0

\large\boxed{\begin{array}{l}\sf a)\\\rm\dfrac{y+4}{y}=\dfrac{6}{4}\\\\\rm 6y=4y+16\\\rm 6y-4y=16\\\rm 2y=16\\\rm y=\dfrac{16}{2}\\\\\rm y=8\\\\\rm\dfrac{x+6}{6}=\dfrac{6}{4}\\\\\rm 4x+24=36\\\rm 4x=36-24\\\rm 4x=12\\\rm x=\dfrac{12}{4}\\\\\rm x=3\end{array}}

\large\boxed{\begin{array}{l}\sf b)\\\rm\dfrac{y}{16}=\dfrac{4}{10}\\\\\rm 10y=64\\\rm y=\dfrac{64\div2}{10\div2}\\\\\rm y=\dfrac{32}{5}\\\rm\dfrac{4,8}{x}=\dfrac{4}{10}\\\\\rm 4x=48\\\rm x=\dfrac{48}{4}\\\\\rm x=12 \end{array}}

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