Question

Me ajudem por favor

Answer 1

Bom dia Katherry!
Solução!

$A)~~3^{2} .3^{8}=3^{2+8}=3^{10}$

$B)~~ \dfrac{2^{20} }{2^{10} }=2^{20} .2^{-10}=2^{20-10}=2^{10}$

$C)~~(3^{2} )^{3}=3^{6}$

$D)~~3^{x}.3^{2}=3^ {x+2}$

$E)~~ \dfrac{2^{x} }{2^{5} }=2^{x}.2^{-5} =2^{x-5}$

$F)~~(3^{x})^{3}=3^{3x}$

Bom dia!
Bons estudos!