Question

Me ajudem nessa questão de sistemas :

Answer 1

a)
2^2(2x).2^y=2^0
4x+y=0
y=-4x.....(1)

2^(x-y)=2^4
x-y=4
y=x-4......(2)

(1)=(2)
-4x=x-4
4=x+4x
4=5x
x=4/5
x=0,8

Em..(2)
y=x-4
y=0.8-4
y=-3,2

b)
5^(2y).5^x=5³
2y+x=3
x=3-2y.......(1)

(4/100)^x=5^y
(1/25)^x=5^y
(1/5²)^x=5^y
5^-2x=5^y
-2x=y
x=-y/2.......(2)

(1)=(2)
3-2y=-y/2
6-4y=-y
6=-y+4y
6=3y
y=6/3
y=2

Em..(2)
x=-2/2
x=-1