Question

me ajudem:
1)calcule:
7 -8
a)(3 .3)$escreva numa unica potencia de base 7: 343^{5} 49^{4}$

Answer 1

343 = $7^{3}$ 

49 =  $7^{2}$

Portanto:

$(7^{3})^5.(7^2)^4 = \\\\ 7^{15}.7^8 = \\\\ 7^{15+8} = \\\\ 7^{23}$

;)