Question

log de 128 na base 1/32 = x ?

Answer 1

$log_{\frac{1}{32}}128 = x \\ \\ \\(2^{-5})^x = 2^7 \\ \\ \\ 2^{-5x} = 2^7 \\ \\ \\ -5x = 7 \\ \\ \\ \boxed{x = -\frac{7}{5}}$