Question

interpole 6 meios aritmeticos entre 62 e 97

Answer 1

P.A.(62,a 2 , a 3 , a 4 , a 5 ,a 6 ,a 7 ,97)
a 1 = 62
a 8 = 97
a 8 = a 1 + (n - 1 ).r
a 8 = 62 + (8 - 1 ).r
97 = 62 + 7 r
97 - 62 = 7 r
35 = 7 r
35 / 7 = r
r = 5
a 2 = a 1 + r
a 2 = 62 + 5 = 67
a 3 = a 2 + r
a 3 = 67 + 5 = 72
a 4 = a 3 + r
a 4 = 72 + 5 = 77
a 5 = a 4 + r
a 5 = 77 + 5 = 82
a 6 = a 5 + r
a 6 = 82 + 5 = 87
a 7 = 87 + 5 = 92
a 8 = 92 + 5 = 97

P.A.(62,67,72,77,82,87,92,97)