Question

efetue as divisões e simplifique os resultados:
$15 \sqrt{6} \div 3 \sqrt{2} \\ \sqrt{ \frac{72}{8} } \\ \sqrt{ \frac{180}{10} } \\ 8 \sqrt{20} \div 4 \sqrt{2} \\ \sqrt[3]{40} \div \sqrt[3]{5}$
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Answer 1

Resposta:

$15\sqrt{6} \div3\sqrt{2} =15\div3\sqrt{6\div2} =5\sqrt{3} \\ \\ \sqrt{{72\over8}} =\sqrt{72\div8} =\sqrt{9} =3\\ \\ \sqrt{{180\over10}} =\sqrt{180\div10} =\sqrt{18} =\sqrt{2.3^2} =3\sqrt{2}$

$8\sqrt{20} \div4\sqrt{2} =8\div4\sqrt{20\div2} =2\sqrt{10} \\ \\ \sqrt[3]{40} \div\sqrt[3]{5} =\sqrt[3]{40\div5} =\sqrt[3]{8} =\sqrt[3]{2^3} =2\\ \\ {20\sqrt{24} \over5\sqrt{3} }=20\div5\sqrt{24\div3} =4\sqrt{8} =4\sqrt{2^2.2} =4.2\sqrt{2} =8\sqrt{2}$