Question

Determinem o numero z em cada caso: a)3z+4i=Z - 6i 20 b) 3zi=z+i

Answer 1

a)
$3z+4i=z-6i+20$
$3z-z=-4i-6i+20$
$2z=-10i+20$
$z=-5i+10$

b)
$3zi=z+1$
$3zi - z = i$
$z(3i-1)=i$
$z=\dfrac{i}{(3i-1)}$