Question

determine o vertice da parabola f(x)=-2x^2-x+3

Answer 1

f(x)= -2x²-x+3

v(xv,yv)

xv= -b/2a
xv= 1/2.(-2)
xv=1/-4

yv= -Δ/4a

Δ= b²-4ac
Δ=1-4.(-2).3
Δ=1+24
Δ=25

yv= -25/4.(-2)
yv=-25/-8
yv=25/8