Question

Determine o valor de x ​

Answer 1

$\large\boxed{\begin{array}{l}\sf x\longrightarrow medida\,do\,raio\\\sf AC=BC=15\\\sf sen(60^\circ)=\dfrac{\frac{15}{2}}{x}\\\sf\dfrac{\sqrt{3}}{\diagup\!\!\!2}=\dfrac{15}{\diagup\!\!\!2x}\\\\\sf \sqrt{3} x=15\\\sf x=\dfrac{15}{\sqrt{3}}\\\\\sf x=\dfrac{15\sqrt{3}}{3}\\\\\sf x=5\sqrt{3}\end{array}}$

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{sen\:{\^A} = \dfrac{a}{2R}}$

$\mathsf{sen\:60\textdegree = \dfrac{\overline{\rm BC}}{2R}}$

$\mathsf{\dfrac{\sqrt{3}}{2} = \dfrac{15}{2x}}$

$\mathsf{x = \dfrac{15}{\sqrt{3}}}$

$\boxed{\boxed{\mathsf{x = 5\sqrt{3}}}}$