Question

Determine o ponto médio dos segmentos abaixo
A - A(3,-4) e B(7,-3)
B - A(5,8) e B(1,-2)

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{A(3,-4)\iff B(7,-3)}$

$\mathsf{M_{AB} = \left(\dfrac{x_A + x_B}{2};\dfrac{y_A + y_B}{2}\right)}$

$\mathsf{M_{AB} = \left(\dfrac{3 + 7}{2};\dfrac{-4 + (-3)}{2}\right)}$

$\mathsf{M_{AB} = \left(\dfrac{3 + 7}{2};\dfrac{-4 - 3}{2}\right)}$

$\mathsf{M_{AB} = \left(\dfrac{10}{2};-\dfrac{7}{2}\right)}$

$\boxed{\boxed{\mathsf{M_{AB} = \left(5;-\dfrac{7}{2}\right)}}}$

$\mathsf{A(5,8)\iff B(1,-2)}$

$\mathsf{M_{AB} = \left(\dfrac{x_A + x_B}{2};\dfrac{y_A + y_B}{2}\right)}$

$\mathsf{M_{AB} = \left(\dfrac{5 + 1}{2};\dfrac{8 + (-2)}{2}\right)}$

$\mathsf{M_{AB} = \left(\dfrac{5 + 1}{2};\dfrac{8 - 2}{2}\right)}$

$\mathsf{M_{AB} = \left(\dfrac{6}{2};\dfrac{6}{2}\right)}$

$\boxed{\boxed{\mathsf{M_{AB} = \left(3;3\right)}}}$